What Is the Probability That a Respondent Is Male and Prefers Arts
Question 323 pts15 students were asked to choose betwixt the broad categories of Arts Science; and Math as their preferred area of study: The results are shown below: What is the probability that a randomly selected respondent is a male or prefers Scientific discipline?Art Scientific discipline MathTotalMale(Female (Total158/150 12/150 4/150 9/15
Question 32 iii pts 15 students were asked to choose between the wide categories of Arts Science; and Math as their preferred area of study: The results are shown beneath: What is the probability that a randomly selected respondent is a male or prefers Science? Art Science Math Total Male (Female (Total 15 8/xv 0 12/fifteen 0 four/15 0 9/fifteen
Question 32 3 pts 15 students were asked to choose betwixt the wide categories of Arts
Science; and Math as their preferred area of study: The results are shown beneath: What is the probability that a randomly selected respondent is a male or prefers Science? Art Science Math Total Male (Female (Full 15 8/fifteen 0 12/15 0 4/15 0 9/15
Okay, And so for this 1, it tells us that there are 32 students in the unabridged course. So I'm just going to write that in the corner of my box. This box represents the biology course, and then it tells us that ten students are, um excuse me, 10 students, our biology majors, bio major on. So it as well tells u.s.a. that 14 students are male and it tells us that of the biology managers for our male. So for our bio major males. Okay, then let'south get in and describe art Venn diagram. And so here'south our fun diagram. So you do that. Then then this four represents this middle role. And we know that because this is the ane that has both a bio major and the males. So if that's the case, and so this 14 represents this unabridged circle. So since we already wrote the four in here, nosotros have to subtract that from the fourteen male person to get just the number of males that air in this column right here, which is just the males that aren't necessarily in bio. So that'due south gonna be 10. And if you add these ii numbers up, you should get xiv, which is true. So so permit's commencement to get this section hither. Then for this section here, that'southward gonna be the bio majors Male. This is the bio majors that aren't necessarily male. So again, we're gonna have to subtract from 10 to iv, which gives us six. So so, if you add these two upwards, you should go 10, which is true again. So then the question asks, Notice the probability that I randomly selected student is male or a bio major. If information technology'south a male or a bio major, that's just this entire state of affairs here. Which means nosotros have to add all the numbers within of here, which is 6 plus iv plus 10. So that means there are twenty students are bio major or male or both. And since we have 32 total in the class, that would be 20 out of 32 which nosotros could simplify that downwardly to 5/8 if we divided both of these by 4. Yep,
This time, right? A liberal arts college. And apparently 5% of the students are studying iii foreign languages. Huh? Sounds well-nigh correct on Dhe. 15% of them are studying languages. Okay. Already writing the calculations because I can see where this is going to become on DDE 45% of sentences that 1 strange language and 35% are studying mill for languages. If they expected number of foreign languages. A pupil studying if y'all select that stupid. And Okay, let'due south compute just to find you lot e'er Well, three times aeroplane zero. It'south just 1.15 And currently is there a place mine and my calculations luck. Uh, they're fine. I get and so hey, expected to be studying 0.9 strange languages, if yous like. They didn't
Okay. Hey, guys, In this trouble, we're told that a student is taking nourish 10 multiple pick question exam and each multiple choice. At that place'south four options, and there'southward exactly one answer. So that means there'south a 1/4 gamble of truth in the right answer and iii/four gamble of choosing a incorrect reply and part A s u.s.a.. One is the probability that the student gets exactly v questions, correct? Getting exactly v questions right implies that there is a one fort. So since at that place's a one in iv chance of getting one question right, there'south a 1/iv chance 14 to the fifth chance, getting for exactly five right and a three/4 to 1/v run a risk of getting the remaining 5 wrong. Just since ah, this is merely assuming this basically, this probability that nosotros but wrote down is assuming that he gets the 1st five right and the next five wrong. Simply there he can become the kickoff. Simply he could get number one wrong, get the next five right and become the terminal four world In order to count for all those possible combinations, we're gonna have to multiply this by 10. Choose five and so 10 shoes five times fourteen to the 5th times 3/4 to the fifth will give us the entire probability of him getting exactly five questions. Correct. And so if we multiply that out, nosotros utilise our calculator. We get that the probability is cipher point 5840.584 And so the probability of him it's getting exactly five questions, right? 0.584 And let'southward do the same process for the next problem. Getting exactly one question correct? That ways that probably him getting ane question right is one for chance and the probability of him getting the rest of the nine questions incorrect is the re fourths to the ninth ability to the 9th Power. And since uh, nosotros don't know which question he gets incorrectly, we're gonna have to multiply this by 10. Cull one, because out of the 10 options he can get at least one correctly fourth dimension. We're choosing the 11 question. He gets correctly out of those 10 options. So if nosotros multiplied this out, that's going to give us our probability of him getting exactly 1 correct reply. And that probability is equivalent to 0.eighteen eight. And that's the answer to Role B.
You know this problem? We are given that we accept a multiple choice question multiple pick test with 25 questions. And so in this 25 and at that place are four options for each test, which means the probability of randomly guessing on one of them and getting it correct Will be a .25. And so we accept our p value at this .25. Yeah. This means that the probability of Ten. Mhm. Following a binomial distribution is 25-6 Times .25 to the X Times .75 To the 25 over again because it follows a binomial distribution. Now on a we desire the probability that student answers more than 20 questions right. So that probably the admission greater than 20 Is equal to the sum as that goes from 21 2025 of our pr that'southward values, We know the p of access. And so this is the sum from admission 21-25 of 25- vi. one.25 to the X. ane.75 25- X. And then here we can but evaluate this on a calculator. We practise this some of 25 choose 10 Times .25 to the ten. .75 To the 25 -X. No affair what the sum to get from 21 to 25. And and then this is going to give u.s.a. 9.677 Times 10 to the -10. No B. Nosotros desire the probability The student answers fewer than five questions correctly. And then X is less than five. This is the sum equally extras from 0-iv because we want to be less than fine enough paperbacks. She'southward the some as extras from 0 to 4 25- six. This .252 there 27 5 to the 25- X. Then nosotros tin can exercise with the exact aforementioned manner we did the previous trouble. We merely alter our premises 20-iv in footstep, and that should requite u.s. uh huh 0.21 37.
5 answers
A={$ small, medium, large $}, B={$ blue, green $}$, and $C={$ triangle, square $}$. List the elements of $A imes C$.
A={$ small, medium, large $}, B={$ blue, green $}$, and $C={$ triangle, square $}$. List the elements of $A imes C$....
i answers
The algebraic expression $2 \sqrt{5 L}$ is used to estimate the speed of a car prior to an blow, in miles per hour, based on the length of its skid marks, $50,$ in anxiety. Observe the speed of a car that left slip marks forty feet long, and write the answer in simplified radical course.
The algebraic expression $2 \sqrt{5 L}$ is used to gauge the speed of a car prior to an accident, in miles per hour, based on the length of its skid marks, $L,$ in feet. Find the speed of a car that left skid marks 40 feet long, and write the answer in simplified radical grade....
Source: https://itprospt.com/num/7363143/question-323-pts15-students-were-asked-to-choose-between
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